x^2-7x+38=5x

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Solution for x^2-7x+38=5x equation:


Simplifying
x2 + -7x + 38 = 5x

Reorder the terms:
38 + -7x + x2 = 5x

Solving
38 + -7x + x2 = 5x

Solving for variable 'x'.

Reorder the terms:
38 + -7x + -5x + x2 = 5x + -5x

Combine like terms: -7x + -5x = -12x
38 + -12x + x2 = 5x + -5x

Combine like terms: 5x + -5x = 0
38 + -12x + x2 = 0

Begin completing the square.

Move the constant term to the right:

Add '-38' to each side of the equation.
38 + -12x + -38 + x2 = 0 + -38

Reorder the terms:
38 + -38 + -12x + x2 = 0 + -38

Combine like terms: 38 + -38 = 0
0 + -12x + x2 = 0 + -38
-12x + x2 = 0 + -38

Combine like terms: 0 + -38 = -38
-12x + x2 = -38

The x term is -12x.  Take half its coefficient (-6).
Square it (36) and add it to both sides.

Add '36' to each side of the equation.
-12x + 36 + x2 = -38 + 36

Reorder the terms:
36 + -12x + x2 = -38 + 36

Combine like terms: -38 + 36 = -2
36 + -12x + x2 = -2

Factor a perfect square on the left side:
(x + -6)(x + -6) = -2

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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